Exercise 1.1

10 => 10 
(+ 5 3 4) => 12
(- 9 1) => 8 
(/ 6 2) => 3
(+ (* 2 4) (- 4 6)) => 6 
(define a 3) 
(define b (+ a 1)) 
(+ a b (* a b)) => 19 
(= a b) => #f 
(if (and (> b a) (< b (* a b))) 
    b 
    a) 
=> 4 
(cond ((= a 4) 6) 
      ((= b 4) (+ 6 7 a)) 
      (else 25)) 
=> 16 
(+ 2 (if (> b a) b a)) => 6
(* (cond ((> a b) a) 
         ((< a b) b) 
         (else -1))  
   (+ a 1))
=> 16